Question

The perimeter of a playing field for a certain sport is 302 ft. The field is a​ rectangle, and the length is 47 ft longer than the width. Find the dimensions. What is the width?

Answer 1

To find the dimensions of a rectangle

Explanation:

perimeter=302

let width=x

length=x+47

p=2(L+W)

302=2(x+x+47)

302=2(2x+47)

302=4x+94

subtracting 94 from the other side we have

302-94=4x

208=4x

x=52

length=99

width=52