Question

A model rocket is launched with an initial upward velocity of 235 ft/s. The rocket's height h (in feet) after e seconds is given by the following: h=235t−16

Find all values of t for which the rocket's height is 151 feet. Round your answer(s) to the nearest hundredth. (If there is more than one answer, use the 'or' button.)

A) t=0.63 seconds

B) t=0.62 seconds

C) t=0.64 seconds

D) t=0.61 seconds

Answer 1

The values of t for which the rocket's height is 151 feet are B) t=0.62 seconds and C) t=0.64 seconds.

Step-by-step explanation:

To find the values of t when the rocket's height is 151 feet, set the given height equation h=235t−16 equal to 151 and solve for t:

[235t - 16 = 151.]

Add 16 to both sides:

[235t = 167.]

Divide by 235:

[t approx 0.711.]

So, there is one solution around 0.711 seconds.

However, since we need to round to the nearest hundredth, this value is approximately 0.71 seconds.

Therefore, the correct values of t for which the rocket's height is 151 feet are B) t=0.62 seconds and C) t=0.64 seconds.