Question

Create a vector of numbers that starts at 6, does not go beyond 55, and adds numbers in increments of 4/7 . So the first three numbers will be 6, 6+4/7, and 6+ 8/7 . How many numbers does the list have?

a) [6,6+ 4/7,6+ 8/7,…,55]

b) [6,6+ 4/7,6+8/7,…,55]

c) [6,6+4/7,6+8/7,…,55]

d) [6,6+ 4/7 ,6+8/7,…,55]

Answer 1

To create a vector of numbers that starts at 6 and does not go beyond 55 in increments of 4/7, the list would have 86 numbers.

Step-by-step explanation:

To create a vector of numbers that starts at 6 and does not go beyond 55, we need to find the numbers that add up to 55 in increments of 4/7. We can start with 6 and gradually add 4/7 to get the next numbers. The pattern would be 6, 6 + 4/7, 6 + (4/7)*2, and so on, until we reach a number close to 55.

Calculating these numbers, we find that the vector would look like [6, 6 + 4/7, 6 + (4/7)*2, ..., 55].

Since the increment is 4/7, we can divide the difference between 55 and 6 by 4/7 to find out how many numbers the list would have. (55 - 6) / (4/7) = 49 / (4/7) = 49 * (7/4) = 86.75. But since we're dealing with whole numbers in the vector, we would round this down to the nearest whole number. Therefore, the list would have 86 numbers.