Final answer:
To solve this problem, we set up a system of equations using 'c' for child tickets and 'a' for adult tickets. By solving the system, we find that 72 child tickets were sold.
Step-by-step explanation:
To solve this problem, we can set up a system of equations to represent the given information. Let's call the number of child tickets sold 'c' and the number of adult tickets sold 'a'. According to the problem, the child admission is $6.30 and the adult admission is $9.40. We can set up the following equations:
c + a = 157
6.30c + 9.40a = 1249.50
We can solve this system of equations to determine the value of 'c'.
From the first equation, we can express 'a' in terms of 'c' as 'a = 157 - c'. Substituting this into the second equation, we get:
6.30c + 9.40(157 - c) = 1249.50
Simplifying the equation:
6.30c + 1472.80 - 9.40c = 1249.50
Combine like terms:
-3.10c + 1472.80 = 1249.50
Subtract 1472.80 from both sides:
-3.10c = -223.30
Divide both sides by -3.10:
c = 72
Therefore, 72 child tickets were sold that day. The correct answer is 72.