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Estimate the size of a crowd standing along a 1.5-mile section of a parade route, with 15 feet deep on both sides of the street, using the ratio of 12 people in 25 square feet.

a. 1,728 people
b. 2,880 people
c. 3,456 people
d. 4,800 people

User Ryan Guill
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1 Answer

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Final answer:

The estimated size of the crowd standing along a 1.5-mile section of a parade route, 15 feet deep on both sides, using a ratio of 12 people per 25 square feet, is approximately 114,432 people.

Step-by-step explanation:

To estimate the size of the crowd standing along a 1.5-mile section of a parade route, with 15 feet deep on both sides of the street, using the ratio of 12 people in 25 square feet, we first need to convert the miles to feet and calculate the total area that the crowd will occupy. There are 5280 feet in a mile, so a 1.5-mile section is 5280 feet * 1.5 = 7920 feet long. Both sides of the street make it 15 feet * 2 for depth, which equals 30 feet. Therefore, the total area is 7920 feet * 30 feet = 237,600 square feet.

Now, using the ratio of 12 people per 25 square feet, we set up a proportion to find the number of people that could fit in 237,600 square feet:

12 people / 25 sq ft = x people / 237,600 sq ft

Solving for x, we get:

x = (12 people * 237,600 sq ft) / 25 sq ft

x = 2,860,800 / 25

x = 114,432 people

Therefore, an estimated 114,432 people can stand along a 1.5-mile section of a parade route, 15 feet deep on both sides of the street, if the crowd is packed at the ratio of 12 people in 25 square feet.

User Vicky Salunkhe
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