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One number is three times bigger than a second. If you add x to each number, their sum is 44. WHAT IS THE BIGGER NUMBER: Write an algebraic equation

a. 3x + x = 44
b. x + 3x = 44
c. 3x - x = 44
d. x - 3x = 44
e. x = 44

1 Answer

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Final answer:

The algebraic equation that represents the situation where one number is three times bigger than another and their sum is 44 when x is added to each is x + 3x = 44. Upon solving, x is found to be 11, thus the bigger number is 3 * 11, which equals 33.

Step-by-step explanation:

To solve for the bigger number in the given equation, let's define two variables. Let x represent the smaller number, and 3x represent the bigger number, since it is three times bigger than the smaller number. According to the problem, if you add x to each number, their sum is 44. Therefore, the algebraic equation that represents this situation is:

x + 3x = 4x = 44

To find the value of x, you would simply divide both sides of the equation by 4:

x = 44/4

x = 11

Now that we have the value of x, we can find the bigger number by multiplying x by 3:

3x = 3 * 11

3x = 33

Therefore, the bigger number is 33.

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