Final answer:
The range of a projectile is zero at projection angles of 90° or 0°. The x-component of a vector is greater than its y-component for angles less than 45°. The angle between tangential velocity and centripetal force vectors is 90°.
Step-by-step explanation:
When examining the conditions for the range of a projectile to be equal to zero, we must consider the angle of projection. The range of a projectile will be zero when the angle of projection is 90° or 0°, because at 90° the projectile goes straight up and comes straight down, and at 0° there is no horizontal component to produce range. Therefore, the correct answer is c. 90° or 0°.
For vector components, the x-component will be larger than the y-component when the angle is less than 45°. This is because at an angle of 45°, the x and y components of a vector are equal, and they decrease symmetrically as the angle moves away from 45° in either direction. The condition for the x-component to be greater is a. 0° < θ < 45°.
The angle formed between the vectors of tangential velocity and centripetal force is always 90° because these two vectors are always perpendicular to each other. Hence, the answer is c. 90°.