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Rank the following diatomic species of fluorine in order of bond length and bond strength.

a) F2 > F2⁺ > F2⁻
b) F2⁻ > F2 > F2⁺
c) F2⁺ > F2⁻ > F2
d) F2 > F2⁻ > F2⁺

User Obcure
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Final answer:

The ranking for diatomic fluorine species in terms of bond strength and bond length from strongest to weakest and shortest to longest is F2+ > F2 > F2-. This is determined by their bond orders, with F2+ having the highest bond order of 1.5 and F2- the lowest at 0.5.

Step-by-step explanation:

Bond Length and Bond Strength in Diatomic Fluorine Species

To rank the diatomic species of fluorine (F2, F2+, and F2-) in order of bond length and bond strength, we consider molecular orbital theory. The bond order is a good predictor of bond strength: the higher the bond order, the stronger and shorter the bond. For fluorine species, we have:

  • F2 has a bond order of 1.
  • F2+ has a bond order of 1.5.
  • F2- has a bond order of 0.5.

Based on these bond orders, F2+ has the strongest and shortest bond while F2- has the weakest and longest bond. Therefore, the correct ranking in order of decreasing bond strength (which correlates with increasing bond length) is F2+ > F2 > F2-, which matches option (c) from the choices provided.

User Slavik Meltser
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