Question

A man starts walking north at 4 ft/s from a point P. What is the man's velocity after 10 seconds?

a) 40 ft/s North
b) 4 ft/s North
c) 14 ft/s North
d) 104 ft/s North

Answer 1

The man's velocity after 10 seconds remains 4 ft/s North as there is no change in speed or direction. Practice problems demonstrate calculations of velocity and displacement using basic physics formulas and vector addition.option b is correct.

Step-by-step explanation:

The question pertains to determining a man's velocity after walking for a given amount of time. Since velocity is a vector quantity expressing both magnitude (speed) and direction, and since there is no change stated in either the speed or direction, the man's velocity after 10 seconds remains unchanged at 4 ft/s North. The other quantities given in the multiple-choice options are incorrect as they imply a change in speed which is not indicated in the problem statement.

Practice Problems

• For the question concerning a trucker's average velocity, the average velocity is the displacement divided by time, resulting in an answer of 4 km/h south.
• Regarding the ball with uniform acceleration, after 10 seconds the velocity can be determined using the formula v = u + at, where u is the initial velocity, a is the acceleration, and t is the time. The ball starts from rest, so u = 0, a = 4 m/s², and t = 10 s. Thus, the velocity of the ball at the end of 10 seconds is 40 m/s.
• The calculation of displacement involves the resultant of two vectors and requires analytical solving or a vector addition method.