Final answer:
The equation of a sine function with amplitude 3 and period 6π is y(x) = 3sin(x/3).
Step-by-step explanation:
The equation of a sine function with amplitude 3 and period 6π can be written as:
y(x) = 3sin(2π/6π(x))
Here, the amplitude is the value in front of the sine function, which is 3.
The period is given by 2π divided by the coefficient of x inside the sine function, which is 6π in this case.
By substituting the values, the equation becomes:
y(x) = 3sin(x/3)