Final answer:
The sample space for tossing three fair coins is {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}. The probability of the dime landing on heads is 3/8 or 0.375.
Step-by-step explanation:
The sample space for this event of tossing three fair coins in order is:
{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}
So, the sample space has 8 outcomes.
The probability of the dime landing on heads can be calculated by looking at the outcomes where the dime lands on heads, which are {HTH, HTT, THH, THT, TTH, TTT}. There are 3 of these outcomes, so the probability is 3/8 or 0.375.