The reaction that shows a double displacement reaction is A. Cu(OH)2 + 2NaCl → CuCl2 + 2NaOH
In a double displacement reaction, the positive ions in two compounds switch places. In this case, Cu( OH )2 ( copper ( II ) hydroxide ) reacts with NaCl ( sodium chloride ) to form CuCl2 ( copper ( II ) chloride ) and NaOH (sodium hydroxide).
This reaction follows the pattern of a double displacement reaction where the positive ions Cu²⁺ and Na⁺ swap places with Cl ⁻ and OH ⁻, respectively, leading to the formation of two new compounds, CuCl2 and NaOH.
Options include:
Cu(OH)2 + 2NaCl → CuCl2 + 2NaOH
Cu(OH)2 + H2SO4 → CuSO4 + 2H2O
Cu(OH)2 + 2KNO3 → Cu(NO3)2 + 2KOH
Cu(OH)2 + 2HCl → CuCl2 + 2H2O