Question

A car in the Dukes of Hazard jumped horizontally off a ledge moving at a speed of 25 m/s. The car landed 15 m away from the base of the ledge. How high is the ledge?

a) 9.8 m
b) 12.8 m
c) 15.6 m
d) 19.6 m

Answer 1

Using the equations of motion, we can determine that the height of the ledge is approximately 2.808 meters.

Step-by-step explanation:

To find the height of the ledge, we can use the horizontal motion equation: d = vx ⁣t. Given that the car landed 15 m away from the base of the ledge and the horizontal velocity (vx) is 25 m/s, we can rearrange the equation to solve for time (t): t = d / vx.

Next, we can use the vertical motion equation: y = vy ⁣t + 0.5 ⁣g ⁣t2. Since the car was launched horizontally, the initial vertical velocity (vy) is 0 m/s. We can rearrange the equation to solve for the height of the ledge (y): y = 0.5 ⁣g ⁣t2.

Plugging in the known values, we get t = 15 m / 25 m/s = 0.6 seconds. Substituting this value into the second equation, we find y = 0.5 ⁣* ⁣9.8 m/s2 ⁣* ⁣0.6 s2 = 2.808 m. Therefore, the height of the ledge is approximately 2.808 meters.