Final answer:
The apparent weight of an object submerged in a fluid is its actual weight minus the buoyant force exerted by the fluid. To find the apparent weight of the 1,025 kg object in a liquid with density 1250 kg/m³, calculate the buoyant force using the object's volume and subtract it from the object's actual weight.
Step-by-step explanation:
The question concerns calculating the apparent weight of an object submerged in a fluid, which involves principles of physics related to buoyancy and Archimedes' Principle. The apparent weight of an object when submerged in a fluid is less than its actual weight in air due to the buoyant force exerted by the fluid. To find the apparent weight, we can use the formula for buoyant force, which is the product of the fluid's density, the volume of the object submerged, and the gravitational acceleration (Fb = ρfluid × Vobject × g). The apparent weight is then calculated by subtracting this buoyant force from the actual weight of the object (Wapparent = Wactual - Fb).
In this case, the actual weight (Wactual) of the 1,025 kg object is its mass times the gravitational acceleration, which is 1,025 kg × 9.81 m/s². The buoyant force is the product of the density of the liquid (1250 kg/m³), the volume of the object (0.275 m³), and the gravitational acceleration. Once we calculate the buoyant force, we can then subtract it from the actual weight to find the apparent weight on the scale.