Question

wind blows over hot liquid placed in a beaker in the laboratory whose avarage room temperature is 27°C. The liquid cooling rate is 15°C/min when it is at temperature of 87°C. Calculate liquid rate of cooling when it's temperature in 57°C​

Answer 1

The question seeks to find the cooling rate of a liquid at 57°C, but without sufficient information to apply Newton's Law of Cooling, it's not possible to calculate the rate accurately.

Step-by-step explanation:

The question asks us to calculate the rate of cooling of a liquid when its temperature is at 57°C given that its cooling rate is 15°C/min at 87°C. To answer this, we would typically use Newton's Law of Cooling, which states that the rate of heat loss of a body is directly proportional to the difference in temperatures between the body and the surroundings.

However, it seems that crucial information is missing to calculate the rate of cooling using Newton's Law, such as the constant of proportionality or the cooling rate at a reference temperature other than 87°C. Without additional information or context, it's impossible to accurately calculate the cooling rate at 57°C.