41.8k views
4 votes
Evaluate the integral ∫(7 - t)√t dt.

a) √t(7 - t) + C
b) (2/3)(7 - t)^(3/2) + C
c) (2/3)(7 - t)^(5/2) + C
d) (2/5)(7 - t)^(5/2) + C

User S M Kamran
by
8.1k points

1 Answer

6 votes

Final answer:

To solve the integral ∫(7 - t)√t dt, we used a substitution method but did not find a match among the provided answer choices. It seems there may have been an error in the question or the response options.

Step-by-step explanation:

Integral Evaluation

To evaluate the integral ∫(7 - t)√t dt, we will use a substitution method. Let us set a substitution u = √t, which implies that t = u^2 and dt = 2u du. Substituting these into the integral gives us ∫(7 - u^2)(2u) du, which simplifies to 2∫(7u - u^3) du. This integral can now be evaluated term by term.

The integral of 7u with respect to u is (7/2)u^2, and the integral of u^3 with respect to u is (u^4)/4. Therefore, the integral becomes 2[(7/2)u^2 - (u^4)/4] + C. Simplifying this, we get 7u^2 - (u^4)/2 + C. When we substitute back for u, we have the final answer 7t - (t^2)/2 + C, which is not among the options given.

It looks like there was a misinterpretation of the original function or options provided in the question. Since the provided options suggest a different form of the integral, possibly involving more transformations and missing constants, without further clarification or correct options, we cannot determine the correct option from the ones provided.

User Justin Homes
by
8.0k points