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Determine the oxidation numbers for each element in the compound H₂SO₄.

User Dominick
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Final answer:

The oxidation numbers in H₂SO₄ are +1 for hydrogen (+1 × 2 = +2), +6 for sulfur, and -2 for oxygen (-2 × 4 = -8), with the overall charge balancing to zero in the compound.

Step-by-step explanation:

To determine the oxidation numbers for each element in the compound H₂SO₄, we follow established rules for assigning oxidation states:

  1. For hydrogen (H), the oxidation number is usually +1.
  2. Oxygen (O) typically has an oxidation number of -2.
  3. The sum of oxidation numbers in a neutral compound must be zero.

Following these rules, for each of the two hydrogen atoms (H₂), the oxidation number is +1, giving a total of +2. There are four oxygen atoms in H₂SO₄, each with an oxidation number of -2, totalling -8. To balance the sum to zero, the sulfur (S) atom therefore must have an oxidation number of +6. So, the oxidation numbers in H₂SO₄ are +1 for hydrogen, +6 for sulfur, and -2 for oxygen.

User Elie Steinbock
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