The calculated value of x in the series is 33
How to determine the value of x
From the question, we have the following parameters that can be used in our computation:
Sum(80) = 470
75th term = 14.5
Sum(X) = 171
The sum of terms of an arithmetic series is represented as

For the first 80 terms, we have

40(2a + 79d) = 470
2a + 79d = 11.75
The nth term of an arithmetic series is represented as
T(n) = a + (n - 1)d
For the 75th term, we have
a + (75 - 1)d = 14.5
a + 74d = 14.5
Multiply by 2
2a + 148d = 29
Subtract 2a + 79d = 11.75 from 2a + 148d = 29
69d = 17.25
So, we have
d = 17.25/69
d = 0.25
Recall that
a + 74d = 14.5
So, we have
a + 74 * 0.25 = 14.5
a + 18.5 = 14.5
a = -4
Recall that
Sum(X) = 171
Using

We have


x(-8 + (x - 1) * 0.25) = 342
Expand
-8x + 0.25x² - 0.25x = 342
0.25x² - 8.25x = 342
Multuply through by 4
x² - 33x - 1368 = 0
Expand
x² + 24x - 57x - 1368 = 0
Factorize
(x + 24)(x - 33) = 0
So, we have
x = -24 or x = 33
The value of x cannot be negative
So, we have
x = 33
Hence, the value of x is 33