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Determine the amplitude (A), period (P), and phase shift (PS) of the function:

f(x) = 8sin(2(x - 4)) + 10

A. A = 8, P = π, PS = (-4, -10)
B. A = 8, P = π, PS = (4, -10)
C. A = 8, P = π, PS = (4, 10)
D. A = 8, P = π, PS = (-4, 10)

User Kotodid
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Final answer:

The amplitude (A) is 8, the period (P) is π, and the phase shift (PS) is 4 units to the right. There is no vertical phase shift, since 10 represents a vertical translation. The correct answer is A = 8, P = π, PS = (4, 10).

Step-by-step explanation:

To determine the amplitude (A), period (P), and phase shift (PS) of the function f(x) = 8sin(2(x - 4)) + 10, we analyze the given function in its standard form f(x) = Asin(B(x - C)) + D.

The amplitude A is the coefficient in front of the sine function, which represents the maximum displacement from the function's midline. In this case, the amplitude is 8.

The period of a sine function is given by P = 2π/B, where B is the coefficient of x within the sine function. For our function, B is 2, thus the period P is π radians.

The phase shift is the horizontal shift of the function along the x-axis, calculated by the value of C in the standard form. The phase shift of this function is 4 units to the right. There is no vertical shift since 10 is the vertical translation, not part of the phase shift.

Therefore, the correct answer is: A = 8, P = π, PS = (4, 10).

User Thomas Kaliakos
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