113k views
0 votes
In a 3.93×10¹g sample of NaHCO₃, how many grams of sodium are present?

a. 9.95g.
b. 15.76g.
c. 23.63g.
d. 31.51g.

User YanivGK
by
7.8k points

1 Answer

1 vote

Final answer:

To find the number of grams of sodium in a 3.93×10¹g sample of NaHCO₃, divide the given mass by the molar mass of NaHCO₃ to convert grams to moles. Finally, multiply the number of moles by the molar mass of sodium to determine the grams of sodium.

Step-by-step explanation:

To find the number of grams of sodium in a 3.93×10¹g sample of NaHCO₃, we need to calculate the molar mass of NaHCO₃ and convert grams to moles. The molar mass of NaHCO₃ is 84.007 g/mol. To convert grams to moles, we divide the given mass by the molar mass:

3.93×10¹g / 84.007 g/mol = 4.68×10⁻¹ mol

Finally, to find the number of grams of sodium, we multiply the number of moles by the molar mass of sodium:

4.68×10⁻¹ mol × 22.990 g/mol ≈ 10.72 g

Therefore, approximately 10.72 grams of sodium are present in the given sample of NaHCO₃.

User Kingindanord
by
8.1k points