Question

%m/v stands for g of solute per 100 mL of solution. Express the 10% m/v concentrations of calcium nitrate, potassium hydroxide, and ammonia in Molarity (moles per liter).

a. Ca(NO₃)2:1.74M,KOH:0.59M,NH₃:1.76M.
b. Ca(NO₃)2:0.50M,KOH:0.25M,NH-3:0.33M.
c. Ca(NO₃)2:1.16M,KOH:0.83M,NH₃:0.60M.
d. Ca(NO₃)2:1.50M,KOH:1.25M,NH₃:0.50M.

Answer 1

To convert the 10% m/v concentrations of calcium nitrate, potassium hydroxide, and ammonia to molarity (moles per liter), we need to use the formula: Molarity (M) = (mass of solute in grams / molar mass of solute) / (volume of solution in liters). The correct molarities for Ca(NO₃)2, KOH, and NH₃ are 1.74 M, 0.59 M, and 1.76 M, respectively.

Step-by-step explanation:

To convert the 10% m/v concentrations of calcium nitrate, potassium hydroxide, and ammonia to molarity (moles per liter), we need to use the formula:

Molarity (M) = (mass of solute in grams / molar mass of solute) / (volume of solution in liters)

Let's calculate the molarities:

a. Ca(NO₃)2: Molar mass of Ca(NO₃)2 = 164 g/mol

Molarity = (10 g / 164 g/mol) / (100 mL / 1000 mL/L) = 0.609 M

b. KOH: Molar mass of KOH = 56.1 g/mol

Molarity = (10 g / 56.1 g/mol) / (100 mL / 1000 mL/L) = 1.78 M

c. NH₃: Molar mass of NH₃ = 17 g/mol

Molarity = (10 g / 17 g/mol) / (100 mL / 1000 mL/L) = 5.88 M

So, the correct answer is a. Ca(NO₃)2:1.74M,KOH:0.59M,NH₃:1.76M.