Final answer:
The distance between second base and home plate is approximately 63.64 ft.
Step-by-step explanation:
To find the distance between second base and home plate, we can use the Pythagorean theorem. Since the baseball diamond is a square, the distance between second and home plate is the same as the distance between first and third base. If we label the distance between first and third base as x, then using the Pythagorean theorem, we can find the distance between second and home plate:
The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. In this case, the distance from first to second base and the distance from second to home plate form a right triangle:
Using the Pythagorean theorem, we can write:
x^2 + x^2 = 90^2
2x^2 = 8100
x^2 = 4050
x ≈ sqrt(4050)
x ≈ 63.64 ft
Therefore, the distance between second base and home plate is approximately 63.64 ft.