Final answer:
In a network diagram using 8-bit host addresses, each subnet can theoretically accommodate 256 addresses, but traditionally, two addresses are reserved for network and broadcast, leaving 254 usable host addresses. The provided options might not take these reservations into account.
Step-by-step explanation:
In a network diagram using 8-bit host addresses, the number of hosts that can be accommodated in each subnet can be calculated by using the formula 2n - 2, where n represents the number of bits used for the host portion of the address. Since we have an 8-bit host address, we calculate 28 - 2 = 256 - 2, which results in 254 usable host addresses. The subtraction of 2 accounts for the network address and the broadcast address.
The options provided in the question seem to ignore the subtraction of 2 addresses that are not assignable to hosts (network and broadcast addresses). If those are not taken into account, using the entire 8-bit range theoretically provides 256 addresses, but as per standard networking practice, the correct answer would be 254 usable addresses.
We must clarify if the question intends for us to include or exclude the network and broadcast addresses. If we are to include them, the answer would be 256 hosts. If we are to exclude these addresses, as per conventional networking protocols, the real number of usable host addresses would be 254.