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For a solution prepared by dissolving 1.90 g of sodium acetate (CH₃COONa), which is the salt of a weak acid and a strong base, what is the pH of the solution?

A. pH less than 7
B. pH equal to 7
C. pH greater than 7
D. Cannot be determined

User Kastulo
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1 Answer

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Final answer:

The pH of the solution prepared by dissolving sodium acetate (CH₃COONa) is greater than 7.

Step-by-step explanation:

The pH of the solution prepared by dissolving 1.90 g of sodium acetate (CH₃COONa) can be determined based on the properties of the salt. Sodium acetate is the salt of a weak acid (acetic acid) and a strong base (sodium hydroxide). When dissolved in water, sodium acetate dissociates into its ions, sodium cations (Na+) and acetate anions (CH₃COO-).

In this case, the acetate ion will act as a weak base and react with water to produce hydroxide ions (OH-) according to the reaction: CH₃COO- + H₂O ⇌ CH₃COOH + OH-. Since the acetate ion is a weaker base compared to the hydroxide ion, it will not significantly affect the pH of the solution, resulting in a pH greater than 7.

Therefore, the correct answer is C. pH greater than 7.

User Nostradamus
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