Final answer:
Using the kinetic energy formula KE = ½ mv², the 0.0020 kg bullet traveling at 400 m/s has 160 Joules of kinetic energy while the 0.0010 kg bullet at 200 m/s has 20 Joules. Therefore, the 0.0020 kg bullet has more kinetic energy.
Step-by-step explanation:
The question asks us to compare the kinetic energy of two bullets with different masses and velocities. The kinetic energy (KE) of an object can be calculated using the formula KE = ½ mv², where m is the mass in kilograms, and v is the velocity in meters per second.
For the 0.0020 kg bullet traveling at 400 m/s, the kinetic energy is:
½ × 0.0020 kg × (400 m/s)²
½ × 0.0020 kg × 160000 (m²/s²)KE = 0.0020 kg × 80000 (m²/s²)KE = 160 (J)
For the 0.0010 kg bullet traveling at 200 m/s, the kinetic energy is:
- ½ × 0.0010 kg × (200 m/s)²
- ½ × 0.0010 kg × 40000 (m²/s²)
- KE = 0.0010 kg × 20000 (m²/s²)
- KE = 20 (J)
Comparing the results, the 0.0020 kg bullet has more kinetic energy than the 0.0010 kg bullet, making option B) More kinetic energy the correct choice.