Question

When does f(x) equal g(x)? What are the x values of the solution?

A. At x = 0; x = 0
B. At x = 1; x = 1
C. At x = 5; x = 5
D. At x = -5; x = -5

Answer 1

The equation x² - 0.00088x + 0.000484 = 0 can be solved using the quadratic formula. The two possible values for x are approximately x = 0.4405 and x = 0.4394.

Step-by-step explanation:

The equation x² - 0.00088x + 0.000484 = 0 can be solved using the quadratic formula.Comparing this equation to the general form ax² + bx + c = 0, we have a = 1, b = -0.00088, and c = 0.000484.

Using the quadratic formula, x = (-b ± √(b² - 4ac)) / (2a), we can substitute the values and solve for x.

The two possible values for x are approximately x = 0.4405 and x = 0.4394.