Question

The expression gives the kinetic energy, in joules, of an object with a mass of m kilograms traveling at a speed of v meters per second. What is the kinetic energy of an experimental unmanned jet with a mass of 1.3 × 10 kg traveling at a speed of about 3.1 × 10 m/s? A. 1.021 × 10² J

B. 1.421 × 10² J
C. 1.815 × 10² J
D. 1.041 × 10² J

Answer 1

The kinetic energy of the experimental unmanned jet can be calculated using the formula KE = 1/2mv², where KE is the kinetic energy, m is the mass, and v is the velocity. Plugging in the given values, the kinetic energy is approximately 1.021 × 10² J.

Step-by-step explanation:

The kinetic energy of an object can be calculated using the formula KE = 1/2mv², where KE is the kinetic energy, m is the mass in kilograms, and v is the velocity in meters per second.

Using this formula, we can calculate the kinetic energy of the experimental unmanned jet with a mass of 1.3 × 104 kg and a speed of about 3.1 × 107 m/s. Plugging in the values, we get:

KE = 1/2 * (1.3 × 104 kg) * (3.1 × 107 m/s)²

Simplifying the equation, we get a kinetic energy of approximately 1.021 × 10² J.