Final answer:
The molar concentration of sodium ions in a 0.350 M Na₃PO₄ solution is 1.05 M, since each mole of Na₃PO₄ produces three moles of sodium ions.
Step-by-step explanation:
The molar concentration of sodium ions (Na⁺) in a 0.350 M Na₃PO₄ solution can be calculated based on the stoichiometry of the compound. Each formula unit of Na₃PO₄ dissociates into three sodium ions (Na⁺) and one phosphate ion (PO⁴³⁺) in solution. Therefore, for every 1 mole of Na₃PO₄, there are 3 moles of Na⁺ ions.
To find the concentration of Na⁺ ions, you multiply the molarity of Na₃PO₄ by the number of Na⁺ ions per formula unit:
0.350 M Na₃PO₄ × 3 mol Na⁺/1 mol Na₃PO₄ = 1.05 M Na⁺.
The molar concentration of sodium ions in a 0.350 M Na₃PO₄ solution is 1.05 M, which corresponds to option C.