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Evaluate dy if y = x³ - 2x² + 1, x=2, and dx = 0.2.

User Yarelis
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Final answer:

To evaluate dy when y = x³ - 2x² + 1, x = 2, and dx = 0.2, we need to find the derivative dy/dx and then substitute the given values.

Step-by-step explanation:

To evaluate dy when y = x³ - 2x² + 1, x = 2, and dx = 0.2, we need to find the derivative dy/dx and then substitute the given values.

1. Find the derivative of y = x³ - 2x² + 1. Differentiating each term separately, we get dy/dx = 3x² - 4x.

2. Substitute x = 2 and dx = 0.2 into the derivative:

dy = (3x² - 4x)dx

Substituting x = 2 and dx = 0.2, we have:

dy = (3(2)² - 4(2))(0.2)

dy = (3(4) - 8)(0.2)

dy = (12 - 8)(0.2)

dy = 4(0.2)

dy = 0.8

User Jzadeh
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