Final answer:
The units for time period t in the equation t = 2π√l/g are seconds (s), as obtained by analyzing the units of each variable and simplifying the expression.
Step-by-step explanation:
The formula t = 2π√l/g is used to calculate the period of a simple pendulum. In this equation, t is the time period, l is the length of the pendulum, and g is the acceleration due to gravity. To determine the units for t, we need to look at the right side of the equation. The square root of length l has units of meters (m), and acceleration due to gravity g has units of meters per second squared (m/s²). When we simplify the expression under the square root, we get √l/g which has units of seconds squared (s²). Taking the square root of this expression provides us with units of seconds (s), and multiplying by the constant 2π (which is unitless) does not affect the units. Therefore, the main answer for the units of t in the equation is seconds (s).