Question

What is the heat capacity of 185 g of liquid water?

Answer 1

The heat capacity of 185 g of liquid water is calculated by multiplying the mass of the water by the specific heat capacity of water, which is 4.184 J/g°C, resulting in 774.04 J/°C.

Step-by-step explanation:

The heat capacity of a substance is the amount of heat required to raise the temperature of a given mass of that substance by 1°C. For liquid water, the specific heat capacity is known to be 4.184 J/g°C. To calculate the heat capacity of 185 g of water, we multiply the mass of the water by its specific heat capacity:

1. Multiply the mass of water (185 g) by the specific heat of water (4.184 J/g°C).
2. Heat Capacity = Mass × Specific Heat = 185 g × 4.184 J/g°C.
3. Heat Capacity = 774.04 J/°C.

Therefore, the heat capacity of 185 g of liquid water is 774.04 Joules per degree Celsius (J/°C).