Question

During contact with a bat, a baseball goes from moving towards the catcher at +82 m/s to moving away from the catcher at -70 m/s. If the ball is in contact with the bat for 0.1 seconds, then what is the acceleration of the ball?

A. 1,520 m/s²
B. -1,520 m/s²
C. 1,520 m/s
D. -1,520 m/s

Answer 1

Option B). The acceleration of the ball is -1520 m/s².

Step-by-step explanation:

To find the acceleration of the ball, we need to calculate the change in velocity and divide it by the time of contact. The initial velocity of the ball is +82 m/s (moving towards the catcher), and the final velocity is -70 m/s (moving away from the catcher). The change in velocity is -70 m/s - (+82 m/s) = -152 m/s.

Given that the time of contact is 0.1 seconds, we can calculate the acceleration using the formula:

acceleration = change in velocity / time of contact

Substituting the values:

acceleration = -152 m/s / 0.1 s = -1520 m/s²

Therefore, the acceleration of the ball is -1520 m/s².