Question

The numbers 1 to 13 are written on 13 separate slips of paper and placed into a box. A slip of paper is randomly drawn from the box. Express probabilities as reduced fractions and as decimals rounded to 3 decimal places.

What is the probability that the slip of paper has an odd number on it?
a) 1/2
b) 2/3
c) 1/3
d) 4/13

Answer 1

The probability of drawing an odd number from slips numbered 1 to 13 is 7 out of 13 or approximately 0.538 when expressed as a decimal.

Step-by-step explanation:

The question asks for the probability that a randomly drawn slip of paper from a box containing slips numbered 1 to 13 will have an odd number. To determine this, we must first identify the total number of outcomes, which is 13, and then count the number of favorable outcomes, which correspond to the odd numbers within 1 to 13.

Odds numbers between 1 and 13 are 1, 3, 5, 7, 9, 11, and 13. There are 7 odd numbers, so our favorable outcomes are 7. Now, we can calculate the probability as the number of favorable outcomes over the total number of outcomes: P(odd) = 7/13.

As a decimal, 7 divided by 13 is approximately 0.538. So the probability of drawing an odd number is 7/13 or 0.538 rounded to three decimal places.