Final answer:
a) Using the ideal gas law, the volume of He will be 9.1 L. b) Using Boyle's Law, the volume of He will be 145.75 ft³. c) Using Charles's Law, the volume of He will remain at 55 ft³. d) Using Gay-Lussac's Law, the pressure of He will remain at 2.65 atm.
Step-by-step explanation:
a) Using the ideal gas law:
Step 1: Convert the temperature to Kelvin: 72ºF = 22.22ºC = 295.37K
Step 2: Convert the pressure to atm: 2000 psig = 2016.16 mmHg = 2.65 atm
Step 3: Substitute the values into the ideal gas law formula:
V₁ = (n₁RT₁) / P₁
V₁ = (1 mol x 0.0821 L·atm/mol·K x 295.37K) / 2.65 atm = 9.1 L
b) Using Boyle's Law:
Step 1: Convert the pressure to atm: 29.85 in Hg = 1 atm
Step 2: Substitute the values into Boyle's Law formula:
P₁V₁ = P₂V₂
2.65 atm x 55 ft³ = 1 atm x V₂
V₂ = (2.65 x 55) / 1 = 145.75 ft³
c) Using Charles's Law:
Step 1: Convert the temperatures to Kelvin: 72ºF = 295.37K
Step 2: Substitute the values into Charles's Law formula:
V₁ / T₁ = V₂ / T₂
55 ft³ / 295.37K = V₂ / 295.37K
V₂ = 55 ft³
d) Using Gay-Lussac's Law:
Step 1: Convert the temperatures to Kelvin: 72ºF = 295.37K
Step 2: Convert the pressure to atm: 2000 psig = 2.65 atm
Step 3: Substitute the values into Gay-Lussac's Law formula:
P₁ / T₁ = P₂ / T₂
2.65 atm / 295.37K = P₂ / 295.37K
P₂ = 2.65 atm