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What is the power of the eye when viewing an object 50.0 cm away?

A) 2.0 D
B) 0.5 D
C) 4.0 D
D) 1.0 D

User Anestis
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1 Answer

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Final answer:

The power of the eye when viewing an object 50.0 cm away can be calculated using the formula Power = 1/focal length. By substituting the given values and solving for the focal length, the power is approximately 0.52 D.

Step-by-step explanation:

The power of the eye when viewing an object can be calculated using the formula:

Power = 1/focal length

The focal length is the distance between the lens and the retina of the eye. In this case, it is given as 2.00 cm. To calculate the power when viewing an object 50.0 cm away, we need to find the focal length for this distance.

Using the formula:

1/focal length = 1/distance to object + 1/distance to retina

Substituting the given values:

1/focal length = 1/50 + 1/2

Solving for the focal length:

focal length = 1 / (1/50 + 1/2)

focal length = 1 / (0.02 + 0.5)

focal length = 1 / 0.52

focal length ≈ 1.92 cm

Now that we have the focal length, we can calculate the power:

Power = 1/focal length

Power ≈ 1 / 1.92 ≈ 0.52 D

User Vivianne
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