Question

What is the theoretical yield of K₃Fe(C₂O₄)3*3H₂O if you reacted 1.0000g of Fe(NH₄)?

A) Calculate based on the molar mass ratio
B) 5.00 g
C) 10.00 g
D) None of the above

Answer 1

Without the balanced chemical equation and additional reaction details, it's not possible to calculate the theoretical yield of K₃Fe(C₂O₄)₃*3H₂O from 1.0000g of Fe(NH₄)₂. The provided examples illustrate similar calculations but are not directly applicable to this scenario.

Step-by-step explanation:

To determine the theoretical yield of K₃Fe(C₂O₄)₃*3H₂O, we would first need the balanced chemical equation for the reaction involving Fe(NH₄)₂ and information about reagents and conditions of the reaction, which are not provided in the question. Hence, with the given information, we cannot definitively calculate the theoretical yield. However, I can guide you on how to approach such a calculation:

1. Determine the balanced chemical equation for the reaction.
2. Convert the mass of the reactant (here, Fe(NH₄)₂) to moles using its molar mass.
3. Apply the stoichiometry from the balanced equation to find the mole ratio between the reactant and the product.
4. Convert the moles of K₃Fe(C₂O₄)₃*3H₂O to grams using its molar mass to find the theoretical yield.

The given problem seems insufficient without the chemical formula for Fe(NH₄)₂ and without knowing the molar mass of K₃Fe(C₂O₄)₃*3H₂O.