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Calculate the standard enthalpy of formation of Ca(OH)2:

a) -985 kJ/mol
b) -522 kJ/mol
c) 985 kJ/mol
d) 522 kJ/mol

1 Answer

1 vote

Final answer:

The question is about finding the standard enthalpy of formation of Ca(OH)2. Without access to the correct standard enthalpy of formation values specific to Ca(OH)2, which are typically found in reference tables like Table T1 or Appendix G, we cannot provide an accurate answer.

Step-by-step explanation:

The subject of the question is Chemistry, specifically Thermochemistry which involves the calculation of standard enthalpy of formation. To calculate the standard enthalpy of formation for a compound such as Ca(OH)2, we would refer to standard enthalpy tables like the one indicated as Table T1 or Appendix G.

The standard enthalpy of formation is defined as the change in enthalpy during the formation of 1 mole of a substance from its constituent elements in their standard states. For elements in their most stable form (like O2, H2, and Ca as a solid), the standard enthalpy of formation is zero.

Although the actual value for the enthalpy change is not provided for Ca(OH)2 directly in the information given, we would be looking for data such as those found in Appendix G to determine the correct answer. With the necessary information, we could carry out the calculation by using the formula:

AH° = AH°products - AH°reactants

The given enthalpy changes for other compounds, such as CO2 and HCl, are irrelevant to the question posed about Ca(OH)2. Thus, among the options provided, without the correct value in the question or relevant references, we cannot confidently determine the correct answer to the question posed.

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