Final answer:
The ADD, LOAD, and JUMP instructions fail to operate correctly if the reg2loc wire is stuck at 0.
Step-by-step explanation:
If the reg2loc wire is stuck at 0, the instructions that will fail to operate correctly are:
- ADD: The ADD instruction adds the contents of two registers and stores the result in a destination register. If the reg2loc wire is stuck at 0, the instruction will always add the value in register 0 to the value in the source register, resulting in incorrect calculations.
- LOAD: The LOAD instruction loads a value from memory into a register. If the reg2loc wire is stuck at 0, the instruction will always load the value from memory address 0 into the register, regardless of the specified memory address.
- JUMP: The JUMP instruction transfers control to a specified memory address. If the reg2loc wire is stuck at 0, the instruction will always jump to memory address 0, leading to incorrect program execution.