Question

Evaluate f(x, y) = eʸ sin(9x) at (π, 0)

A) 0
B) e^π
C) e⁰
D) sin(9π)"

Answer 1

Evaluating the function f(x, y) at (π, 0) leads to a value of 0 since e⁰ is 1 and sin(9π) is 0. The correct option we have 1 × 0 = 0, which means that the evaluated function equals 0, corresponding to option A).

Step-by-step explanation:

Evaluating the function f(x, y) at (π, 0) leads to a value of 0 since e⁰ is 1 and sin(9π) is 0.

To evaluate the function f(x, y) = e˥ sin(9x) at the point (π, 0), we simply substitute the x and y values into the function. So, f(π, 0) becomes e⁰ sin(9π).

Knowing that e⁰ equals 1 (since any number raised to the power of 0 is 1), and that sin(9π) equals 0 (because sine of any integer multiple of π is always 0), we can easily determine the value of the function at this point.

Therefore, we have 1 × 0 = 0, which means that the evaluated function equals 0, corresponding to option A).