Final answer:
The question is related to physics asking for the post-collision velocity of a car that hit a deer, whilst assuming the deer remains on the car. This involves using the principle of conservation of momentum to calculate the velocity after the collision.
Step-by-step explanation:
Calculating the Post-Collision Velocity of a Car and Deer
The problem in question is a classic example of a conservation of momentum problem in physics. We are given a scenario in which a 900-kg car initially moving at 30.0 m/s collides with a 150-kg deer running in the same direction at 12.0 m/s. The question asks for the velocity of the car immediately after the collision, assuming that the deer remains attached to the car. To solve this problem, we would apply the principle of conservation of momentum, which states that if no external forces are acting on a system, the total momentum before an event (like a collision) is equal to the total momentum after the event. The momentum of each object is calculated by the product of its mass and velocity. For the car (m1 = 900 kg, v1 = 30.0 m/s) and the deer (m2 = 150 kg, v2 = 12.0 m/s), the combined momentum before the collision is the sum of their individual momenta. After the collision, the new combined mass (m1 + m2) will move with the same momentum, but we need to solve for the new velocity (v').
The momentum before the collision is:
(m1 * v1) + (m2 * v2)
The momentum after the collision is:
(m1 + m2) * v'
By equating the two and solving for v', we find the velocity of the car just after collision. This is a typical kinematics scenario that involves momentum calculation.