Final answer:
To find the number of grams of H₂ in 0.31 mol of (C₃H₅)₂S, multiply the number of moles of (C₃H₅)₂S by the mole-to-mole ratio between (C₃H₅)₂S and H₂.
Step-by-step explanation:
To find the number of grams of H₂ in 0.31 mol of (C₃H₅)₂S, we first need to determine the molar mass of H₂. The molar mass of H₂ is 2 g/mol, since each molecule of H₂ weighs 2 grams.
Next, we can use the mole-to-mole ratio between (C₃H₅)₂S and H₂. From the balanced chemical equation of the reaction, we can see that for every 1 mol of (C₃H₅)₂S, there are 2 mol of H₂.
Therefore, the number of grams of H₂ in 0.31 mol of (C₃H₅)₂S is calculated as: 0.31 mol x 2 g/mol = 0.62 grams of H₂.