Question

Try a star question: A ball is thrown straight up into the air with an initial velocity given by v = 85t - 16. Find the average velocity by the ball from 0.2 to 0.1 seconds.

a. 85 m/s
b. 42.5 m/s
c. -16 m/s
d. 0 m/s

Answer 1

The average velocity of the ball between 0.2 and 0.1 seconds, calculated from the provided velocity-time equation, is -3.25 m/s, which does not match any of the provided options.

Step-by-step explanation:

To find the average velocity of the ball from 0.2 to 0.1 seconds using the given velocity equation v = 85t - 16, we need to calculate the velocities at both times and then find the average of these two velocities.

First, we find the velocity at 0.2 seconds:

v(0.2) = 85(0.2) - 16 = 17 - 16 = 1 m/s

Next, we find the velocity at 0.1 seconds:

v(0.1) = 85(0.1) - 16 = 8.5 - 16 = -7.5 m/s

Now, we calculate the average of these two velocities:

Average velocity = (v(0.2) + v(0.1)) / 2 = (1 m/s - 7.5 m/s) / 2 = -3.25 m/s

None of the options provided (a. 85 m/s, b. 42.5 m/s, c. -16 m/s, d. 0 m/s) match the calculated average velocity, so there may be a mistake in the provided options or the setup of the question.