Final answer:
The angular momentum of an electron in a 4s orbital is 0 because the angular momentum quantum number (l) for an s orbital is 0.
Step-by-step explanation:
The angular momentum of electrons in orbitals is determined by their quantum numbers. For an electron in a 4s orbital, the angular momentum quantum number l is 0. In quantum mechanics, the magnitude of an electron's angular momentum in an orbital is given by the formula L = √(l(l+1))ħ, where ħ (h-bar) is the reduced Planck's constant, which equals h/(2π). Thus, for an electron in a 4s orbital with l = 0, the angular momentum would be L = √(0(0+1))ħ = 0. Therefore, the correct answer is: a) 0