185k views
5 votes
If theta is 225°, how do you solve for sin, cos, tan?

a) sin(225°) = -√2/2, cos(225°) = -√2/2, tan(225°) = 1
b) sin(225°) = -√2/2, cos(225°) = √2/2, tan(225°) = -1
c) sin(225°) = √2/2, cos(225°) = -√2/2, tan(225°) = -1
d) sin(225°) = √2/2, cos(225°) = -√2/2, tan(225°) = 1

User Gadlol
by
8.9k points

1 Answer

1 vote

Final answer:

In solving for sin(225°), cos(225°), and tan(225°), both sine and cosine are negative √2/2 due to the angle's placement in the third quadrant, and the tangent is 1.

Step-by-step explanation:

To solve for sin(225°), cos(225°), and tan(225°), we must consider the properties of the unit circle. An angle of 225° is located in the third quadrant, where both sine and cosine values are negative.

By using the reference angle of 45°, which corresponds to 225° in the unit circle, we know the sine and cosine values will be √2/2 in magnitude but negative due to the angle's location in the third quadrant.

Therefore, sin(225°) = -√2/2 and cos(225°) = -√2/2. For the tangent function, which is the ratio of sine to cosine, the negatives cancel each other out, leading to tan(225°) = 1.

The correct answer is a) sin(225°) = -√2/2, cos(225°) = -√2/2, tan(225°) = 1.

User Jacques Carette
by
8.3k points

Related questions

asked Apr 1, 2019 210k views
Andy Nuss asked Apr 1, 2019
by Andy Nuss
8.6k points
2 answers
1 vote
210k views
1 answer
1 vote
76.5k views