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Why is root 2 over 2 equal to one over root 2?

User Hlung
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Final answer:

The equality of
\(√(2)/2\) and \(1/√(2)\) is shown by rationalizing the denominator of the latter, which involves multiplying the numerator and denominator by
\(√(2)\) thereby transforming it into the former while maintaining its value.

Step-by-step explanation:

The question at hand is about simplifying radical expressions, specifically why
\(√(2)/2\) is equal to
\(1/√(2)\). To understand this, we need to look at the properties of radicals and fractions. When we simplify a fraction, we aim to find an equivalent fraction with a simpler form. In this case, the trick lies in rationalizing the denominator. To rationalize the denominator of
\(1/√(2)\) we could multiply both the numerator and the denominator by
\(√(2)\). This process of multiplying by the same quantity on the top and the bottom ensures that the overall value does not change (since multiplying by
1 does not alter the value of a number) but it changes the appearance of the fraction. When we multiply
\(1/√(2)\)by
\(√(2)/√(2)\, we end up with
\(√(2)/2\), which is the same as the original expression.

Thus, multiplying by a cleverly disguised form of 1 (in this case,


\(√(2)/√(2)\)), preserves equality and rationalizes the denominator, showing how the two expressions
\(√(2)/2\) and
\(1/√(2)\) are indeed equal.

User MMP
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