Final answer:
The net ionic equation of the reaction between BeCl₂ and NaOH is Be²⁺(aq) + 2OH⁻(aq) → Be(OH)₂(s).
Step-by-step explanation:
The reaction between BeCl₂ and NaOH can be represented by the following balanced equation:
BeCl₂ + 2NaOH → Be(OH)₂ + 2NaCl
In this reaction, BeCl₂ reacts with NaOH to form Be(OH)₂ and NaCl.
To determine the net ionic equation, we need to identify the ionic compounds that dissociate into ions in solution.
In this case, the soluble compounds are NaOH and NaCl.
The net ionic equation can be obtained by eliminating the spectator ions, which are ions that do not undergo a chemical change during the reaction.
In this reaction, the spectator ions are Na⁺ and Cl-.
Therefore, the net ionic equation is: Be²⁺(aq) + 2OH⁻(aq) → Be(OH)₂(s)