Question

If the average student's arms can extend about 1.3m, how many students would have to join hands to form a human chain around a giant sequoia tree?

Answer 1

To form a human chain around a giant sequoia with an
`8-meter` diameter we calculate the circumference and divide it by two students' combined arm spans. It would take
`10` students to form the chain.

Step-by-step explanation:

To find out how many students would have to join hands to form a human chain around a giant sequoia tree, we need to estimate the circumference of the giant sequoia tree's trunk and then divide that by the length that a student's arms can extend. To simplify the calculation, let's assume a mature giant sequoia has a diameter of around 8 meters. The circumference of a circle is calculated by the formula
`C = π x d`,

where
`C` is the circumference and d is the diameter.

Using the diameter of
`8 meters` :
`C = π x 8m = 25.13m` (using
`3.14159 for π`).

Next, if each student's arm span is
`1.3 meters` , two students' combined arm span would be
`2.6 meters`. Therefore, to cover the circumference of
`25.13 meters`, we would divide
`25.13m` by
`2.6m` to get approximately
`9.67.` Since we can't have a fraction of a student, we round up to the nearest whole number.

It would take
`10` students to form a human chain around the tree with their hands joined.