Question

A rectangular wooden block of weight floats with exactly one-half of its volume below the waterline. What is the buoyant force acting on the block?

a. 2w
b. w
c. 1/2w
d. )the bouyant force cannot be determined
The density of water is 1.00g/cm³ . What is the density of the block?
a. 2.00 g/cm³
b. between 1.00 and 2.00 g/cm³
c. 1.00 g/c/m³
d. between 0.50 and 1.00 g/cm³
e. 0.50 g/cm³
f. density cannnot be determined

Answer 1

The buoyant force on a block floating with half its volume submerged is equal to its weight, and the block's density is half that of water, 0.50 g/cm³.

Step-by-step explanation:

The question relates to the physics concept of buoyancy, as described by Archimedes' principle. This principle states that the buoyant force on an object is equal to the weight of the fluid it displaces. In the case of a wooden block floating in water with half of its volume submerged, the buoyant force is equal to the weight of the block (w), as it displaces a volume of water that weighs the same as the block itself (option b. w).

To determine the density of the block, we note that it floats with half of its volume submerged, which indicates that its density is equal to half the density of water. Since the density of water is 1.00 g/cm³, the density of the block must be 0.50 g/cm³ (option e. 0.50 g/cm³).