Question

The sum of six consecutive integers is 243. Find the integers .

Answer 1

To find the six consecutive integers whose sum is 243, assume the first integer is n. The next five consecutive integers would be (n+1), (n+2), (n+3), (n+4), and (n+5). Their sum would be 6n + 15 = 243. Dividing both sides by 6, we find n = 38. So the six consecutive integers are 38, 39, 40, 41, 42, and 43.

Step-by-step explanation:

To find the six consecutive integers whose sum is 243, we can use algebra. Let's assume the first integer is n. The next five consecutive integers would be (n+1), (n+2), (n+3), (n+4), and (n+5). Their sum would be:

n + (n+1) + (n+2) + (n+3) + (n+4) + (n+5) = 243

Combining like terms, we have:

6n + 15 = 243

Simplifying the equation gives:

6n = 228

Dividing both sides by 6, we find:

n = 38

So the six consecutive integers are 38, 39, 40, 41, 42, and 43.