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Find the output

L[5,9,13,5,8,2,1]
L.append([11,22])
L.extend([11,22])
L.count(5)
L.count(15)
L.insert(100,2)
L.index(5)
L.pop(5)
L.remove(3)
L.clear( )


information practices (IP) questions ​

User Nolesh
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1 Answer

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Final answer:

The question involves performing various list operations in Python on the list L [5,9,13,5,8,2,1]. Operations include appending, extending, counting occurrences, inserting at a specific index, finding the index of an element, popping elements, removing elements, and clearing the list.

Step-by-step explanation:

Understanding List Operations in Python

Considering the provided list L which initially has the elements [5,9,13,5,8,2,1], applying different list operations would result in the following changes:

  • L.append([11,22]) - Adds the list [11, 22] as a single element to the end of L, making it [5,9,13,5,8,2,1,[11,22]].
  • L.extend([11,22]) - Extends the list by adding elements 11 and 22 to it, resulting in [5,9,13,5,8,2,1,11,22] if extend is called after the initial list without the append operation.
  • L.count(5) - Counts how many times the value 5 appears in the list, which would be 2 times initially.
  • L.count(15) - Counts the occurrences of 15 in the list, which would be 0 since 15 is not in the list.
  • L.insert(100,2) - Inserts the value 2 at the index 100. This will just add 2 at the end of the list because the index 100 exceeds the length of the list.
  • L.index(5) - Returns the index of the first occurrence of 5, which would be 0.
  • L.pop(5) - Removes the element at index 5, which is 2, and returns it.
  • L.remove(3) - Tries to remove the first occurrence of the value 3 from the list, which would result in a ValueError since 3 is not in the list.
  • L.clear() - Empties the list, leaving it as [].

Note that each operation mutates the list and therefore affects the subsequent operations.

User Saca
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